100 posts untill a mod

[007coolcube]

2x5(1+2)+5


Just woke up.. On ipod..

[Neko92]

34 to 45?

Your math Cube, it confuses me.

http://gyazo.com/737fbdc5b685d3c674445eccb48075a7

[007coolcube]

was meant to be 1+2... was like.. 7 AM in the morning.. don't judge

1

[Nahuda]

Let's say 1 is in N.
If x is in N, then its "successor" x' is in N.
There is no x such that x' = 1.
If x isn't 1, then there is a y in N such that y' = x.
If S is a subset of N, 1 is in S, and the implication (x in S => x' in S) holds, then S = N.
Let a and b be in N.
If b = 1, then define a + b = a'
If b isn't 1, then let c' = b, with c in N and define a + b = (a + c)'.
Using this definition, we can determine that 1 + 1 does in fact equal 2.

[007coolcube]

1585x2632=3.

End of story.

[pyrusbrawler30]

4's!

[morpher26]

5

[Nahuda]

Just 6.

[007coolcube]

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[zuko135]

Let's say 1 is in N.
If x is in N, then its "successor" x' is in N.
There is no x such that x' = 1.
If x isn't 1, then there is a y in N such that y' = x.
If S is a subset of N, 1 is in S, and the implication (x in S => x' in S) holds, then S = N.
Let a and b be in N.
If b = 1, then define a + b = a'
If b isn't 1, then let c' = b, with c in N and define a + b = (a + c)'.
Using this definition, we can determine that 1 + 1 does in fact equal 2.

You just BLEW my mind!

5

How is morpher mod?
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My turn... Wait for it...
(>^_^)>8 I gave you a number '8' lawl
Fancy right? Lol